Solve.
-$\begin{aligned} x + 5 y + 3 z & = - 22 \ 5 y + 4 z & = - 30 \ z & = - 5 \ ( 3 , - 2 , - 5 ) \end{aligned}$
A) Yes
B) No

Question

Quizplus · Accepted Answer

Given $z = -5$, substituting $z$ into the second equation gives $5y + 4(-5) = -30$, which simplifies to $5y - 20 = -30$, leading to $5y = -10$, and thus $y = -2$. Substituting $y = -2$ and $z = -5$ into the first equation gives $x + 5(-2) + 3(-5) = -22$, which simplifies to $x - 10 - 15 = -22$, leading to $x = 3$. Therefore, the solution $(3, -2, -5)$ is correct.

Solve - x+5y+3z=−225y+4z=−30z=−5(3,−2,−5)\begin{aligned} x + 5 y + 3 z & = - 22 \\ 5 y + 4 z & = - 30 \\ z & = - 5 \\ ( 3 , - 2 , - 5 ) \end{aligned}x+5y+3z5y+4zz(3,−2,−5)​=−22=−30=−5​

Solve
- $\begin{aligned} x + 5 y + 3 z & = - 22 \\ 5 y + 4 z & = - 30 \\ z & = - 5 \\ ( 3 , - 2 , - 5 ) \end{aligned}$