Solve.
-A newspaper carrier has $2.30 in change. He has two more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he have?
A)5 quarters, 3 dimes, 15 nickels
B)15 quarters, 13 dimes, 5 nickels
C)7 quarters, 5 dimes, 21 nickels
D)5 quarters, 7 dimes, 15 nickels

Question

Quizplus · Accepted Answer

The total value of the coins is $2.30. Let the number of dimes be d, quarters be q, and nickels be n. The relationships are q = d + 2 and n = 3q. Using the values of coins (5 cents for a nickel, 10 cents for a dime, and 25 cents for a quarter), the equation is 5n + 10d + 25q = 230. Substituting the relationships into the equation and solving gives 5(3q) + 10(q - 2) + 25q = 230, which simplifies to 15q + 10q - 20 + 25q = 230. Solving this gives q = 5, d = 3, and n = 15.

Solve. -A Newspaper Carrier Has $2.30 in Change. He Has Two