Solve the inequality. -$$- 14 x + 16 \leq - 2 ( 6 x - 9 )$$ A) $x - 1$ B) $x \geq - 1$ C) $x

Name: Solve the inequality. -\[- 14 x + 16 \leq - 2 ( 6 x - 9 )\] A) $x > - 1$ B) $x \geq - 1$ C) $x < - 1$ D) $x \leq - 1$
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Question

Solve the inequality.
-$$- 14 x + 16 \leq - 2 ( 6 x - 9 )$$
A) $x > - 1$
B) $x \geq - 1$
C) $x < - 1$
D) $x \leq - 1$

Quizplus · Accepted Answer

First, distribute the -2 on the right side: $-2(6x - 9) = -12x + 18$. The inequality becomes $-14x + 16 \leq -12x + 18$. Add $12x$ to both sides: $-2x + 16 \leq 18$. Subtract 16 from both sides: $-2x \leq 2$. Divide by -2 (and reverse the inequality sign): $x \geq -1$.

Solve the Inequality −14x+16≤−2(6x−9)- 14 x + 16 \leq - 2 ( 6 x - 9 )−14x+16≤−2(6x−9)

Solve the Inequality $- 14 x + 16 \leq - 2 ( 6 x - 9 )$