Solve the Inequality $$\frac { 7 } { 18 } ( x + 2 ) > \frac { 1 } { 6 } ( x + 5 )$$

Solve the inequality.
- $$\frac { 7 } { 18 } ( x + 2 ) > \frac { 1 } { 6 } ( x + 5 )$$

A) $x > - 0.25$
B) $x <$
C) $x >$
D) $x < - 0.25$