Fill in the missing entries in the following partially completed one -way ANOVA table. $$\begin{array} { l | c | c | c | c }
\text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & & & 11.16 \
\hline \text { Error } & & 13.72 & 0.686 &
\end{array}$$
A)$$\begin{array} { l | c | c | c | c }
\text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { f } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 22.97 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 36.69 & &
\end{array}$$
B)$$\begin{array} { l | c | c | c | c }
\text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 2.55 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 16.27 & &
\end{array}$$
C)$$\begin{array} { l | c | c | c | c }
\text { Source } & d f & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { d } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 48.80 & 16.27 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 62.52 & &
\end{array}$$
D)$$\begin{array} { l | c | c | c | c }
\text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / \boldsymbol { d f } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 0.184 & 0.061 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 13.90 & &
\end{array}$$

Question

Fill in the missing entries in the following partially completed one -way ANOVA table. $$\begin{array} { l | c | c | c | c } 
\text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & & & 11.16 \
\hline \text { Error } & & 13.72 & 0.686 &
\end{array}$$
A)$$\begin{array} { l | c | c | c | c } 
\text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { f } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 22.97 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 36.69 & &
\end{array}$$
B)$$\begin{array} { l | c | c | c | c } 
\text { Source } & d \boldsymbol { f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d f & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 2.55 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 16.27 & &
\end{array}$$
C)$$\begin{array} { l | c | c | c | c } 
\text { Source } & d f & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / d \boldsymbol { d } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 48.80 & 16.27 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 62.52 & &
\end{array}$$
D)$$\begin{array} { l | c | c | c | c } 
\text { Source } & \boldsymbol { d f } & \boldsymbol { S S } & \boldsymbol { M S } = \boldsymbol { S S } / \boldsymbol { d f } & \boldsymbol { F } \text {-statistic } \
\hline \text { Treatment } & 3 & 0.184 & 0.061 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 13.90 & &
\end{array}$$

Quizplus · Accepted Answer

The correct SS for Treatment is found by multiplying the MS of Treatment by its df, which gives $7.66 \times 3 = 22.97$. The df for Error is calculated by subtracting the Treatment df from the Total df, giving $23 - 3 = 20$. The Total SS is the sum of the Treatment SS and the Error SS, which is $22.97 + 13.72 = 36.69$.

Fill in the Missing Entries in the Following Partially Completed