Human body temperatures have a mean of $98.20 ^ { \circ } \mathrm { F }$ and a standard deviation of $0.62 ^ { \circ } \mathrm { F } _ { 4 }$ Sally's temperature can be described by z=-1.5 . What is her temperature? Round your answer to the nearest hundredth.
A) $97.27 ^ { \circ } \mathrm { F }$
B) $99.13 ^ { \circ } \mathrm { F }$
C) $96.70 ^ { \circ } \mathrm { F }$
D) $95.79 ^ { \circ } \mathrm { F }$

Question

Human body temperatures have a mean of $98.20 ^ { \circ } \mathrm { F }$ and a standard deviation of $0.62 ^ { \circ } \mathrm { F } _ { 4 }$ Sally's temperature can be described by  z=-1.5 . What is her temperature? Round your answer to the nearest hundredth.
A) $97.27 ^ { \circ } \mathrm { F }$
B) $99.13 ^ { \circ } \mathrm { F }$
C) $96.70 ^ { \circ } \mathrm { F }$
D) $95.79 ^ { \circ } \mathrm { F }$

Quizplus · Accepted Answer

Sally's temperature is calculated using the formula for a z-score: $Z = \frac{(X - \mu)}{\sigma}$, where $X$ is Sally's temperature, $\mu = 98.20^\circ F$ is the mean temperature, and $\sigma = 0.62^\circ F$ is the standard deviation. Rearranging the formula to solve for $X$ gives $X = Z \cdot \sigma + \mu$. Substituting $Z = -1.5$, $\sigma = 0.62$, and $\mu = 98.20$, we get $X = -1.5 \cdot 0.62 + 98.20 = 97.27^\circ F$.

Human Body Temperatures Have a Mean Of 98.20∘F98.20 ^ { \circ } \mathrm { F }98.20∘F

Human Body Temperatures Have a Mean Of $98.20 ^ { \circ } \mathrm { F }$