The force in member FE of the plane truss below is approximately: (A) $ -1.5 \mathrm{kN} $ (
B) $ -2.2 \mathrm{kN} $ (
C) $ 3.9 \mathrm{kN} $ (
D) $ 4.7 \mathrm{kN} $

Question

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The Answer of The force in member FE of the plane truss below is approximately: (A) $ -1.5 \mathrm{kN} $ (
B) $ -2.2 \mathrm{kN} $ (
C) $ 3.9 \mathrm{kN} $ (
D) $ 4.7 \mathrm{kN} $

The Force in Member FE of the Plane Truss Below −1.5kN -1.5 \mathrm{kN} −1.5kN

The Force in Member FE of the Plane Truss Below $-1.5 \mathrm{kN}$