The matrix $\left[\begin{array}{rrr}
1 / 2 & -1 & 1 / 2 \
1 / 2 & 0 & -1 / 2 \
-1 / 2 & 1 & 1 / 2
\end{array}\right]$
is the inverse of
$\left[\begin{array}{lll}
1 & 2 & 1 \
0 & 1 & 1 \
1 & 0 & 1
\end{array}\right]$
Solve the following system by the
inverse matrix method.
x+2 y+z =10
y+z =6
x+z =-8

Question

The matrix $\left[\begin{array}{rrr}
1 / 2 & -1 & 1 / 2 \
1 / 2 & 0 & -1 / 2 \
-1 / 2 & 1 & 1 / 2
\end{array}\right]$
is the inverse of
$\left[\begin{array}{lll}
1 & 2 & 1 \
0 & 1 & 1 \
1 & 0 & 1
\end{array}\right]$
Solve the following system by the
inverse matrix method.
x+2 y+z =10 
y+z =6  
x+z =-8

Quizplus · Accepted Answer

The Answer of The matrix $\left[\begin{array}{rrr}
1 / 2 & -1 & 1 / 2 \
1 / 2 & 0 & -1 / 2 \
-1 / 2 & 1 & 1 / 2
\end{array}\right]$
is the inverse of
$\left[\begin{array}{lll}
1 & 2 & 1 \
0 & 1 & 1 \
1 & 0 & 1
\end{array}\right]$
Solve the following system by the
inverse matrix method.
x+2 y+z =10 
y+z =6  
x+z =-8

The Matrix [1/2−11/21/20−1/2−1/211/2]\left[\begin{array}{rrr}1 / 2 & -1 & 1 / 2 \\1 / 2 & 0 & -1 / 2 \\-1 / 2 & 1 & 1 / 2\end{array}\right]​1/21/2−1/2​−101​1/2−1/21/2​​

The Matrix $\left[\begin{array}{rrr}1 / 2 & -1 & 1 / 2 \\1 / 2 & 0 & -1 / 2 \\-1 / 2 & 1 & 1 / 2\end{array}\right]$