The inverse of matrix $\left[\begin{array}{lll}
1 & 1 & 0 \
1 & 2 & 1 \
2 & 3 & 2
\end{array}\right] \text { is }\left[\begin{array}{rrr}
1 & -2 & 1 \
0 & 2 & -1 \
-1 & -1 & 1
\end{array}\right]$
Solve the following system by the method of inverse matrix.
$\begin{array}{r}
x+y=15 \
x+2 y+z=20 \
2 x+3 y+2 z=12
\end{array}$

Question

Quizplus · Accepted Answer

The Answer of The inverse of matrix $\left[\begin{array}{lll}
1 & 1 & 0 \
1 & 2 & 1 \
2 & 3 & 2
\end{array}\right] \text { is }\left[\begin{array}{rrr}
1 & -2 & 1 \
0 & 2 & -1 \
-1 & -1 & 1
\end{array}\right]$
Solve the following system by the method of inverse matrix.
$\begin{array}{r}
x+y=15 \
x+2 y+z=20 \
2 x+3 y+2 z=12
\end{array}$

The Inverse of Matrix Solve the Following System by the Method of Inverse Matrix