The following table presents the probability distribution of the number of vacations X taken last year for a randomly chosen family. Find P(1 or more)
$\begin{array} { c | c c c c c }
x & 0 & 1 & 2 & 3 & 4 \
\hline P ( x ) & 0.15 & 0.56 & 0.15 & 0.1 & 0.04
\end{array}$
A)0.29
B)0.56
C)0.71
D)0.85

Question

The following table presents the probability distribution of the number of vacations X taken last year for a randomly chosen family. Find P(1 or more)
 $\begin{array} { c | c c c c c } 
x & 0 & 1 & 2 & 3 & 4 \
\hline P ( x ) & 0.15 & 0.56 & 0.15 & 0.1 & 0.04
\end{array}$
A)0.29
B)0.56
C)0.71
D)0.85

Quizplus · Accepted Answer

To find $P(1 \text{ or more})$, we sum the probabilities of taking 1, 2, 3, or 4 vacations: $0.56 + 0.15 + 0.1 + 0.04 = 0.85$.

The Following Table Presents the Probability Distribution of the Number x01234P(x)0.150.560.150.10.04\begin{array} { c | c c c c c } x & 0 & 1 & 2 & 3 & 4 \\\hline P ( x ) & 0.15 & 0.56 & 0.15 & 0.1 & 0.04\end{array}xP(x)​00.15​10.56​20.15​30.1​40.04​​

The Following Table Presents the Probability Distribution of the Number $\begin{array} { c | c c c c c } x & 0 & 1 & 2 & 3 & 4 \\\hline P ( x ) & 0.15 & 0.56 & 0.15 & 0.1 & 0.04\end{array}$