For the data set below, find the upper outlier boundary.
$\begin{array} { l l l l l l l l l l l }
\hline 160 & 176 & 193 & 144 & 163 & 146 & 152 & 158 & 154 & 184 & 129 \
\hline
\end{array}$
A)221
B)176
C)30
D)193

Question

For the data set below, find the upper outlier boundary.
 $\begin{array} { l l l l l l l l l l l } 
\hline 160 & 176 & 193 & 144 & 163 & 146 & 152 & 158 & 154 & 184 & 129 \
\hline
\end{array}$
A)221
B)176
C)30
D)193

Quizplus · Accepted Answer

The upper outlier boundary is calculated using the formula: Q3 + 1.5 * IQR, where Q3 is the third quartile and IQR is the interquartile range (Q3 - Q1). For the given data set, after sorting: 129, 144, 146, 152, 154, 158, 160, 163, 176, 184, 193, Q1 (the first quartile) is 152, and Q3 (the third quartile) is 176. The IQR is 176 - 152 = 24. Therefore, the upper outlier boundary is 176 + 1.5 * 24 = 176 + 36 = 212. Since 212 is not an option, the calculation needs to be revisited for accuracy. Correctly calculating gives Q3 + 1.5*IQR = 176 + 1.5*24 = 212, indicating a mistake in the initial explanation. The correct approach involves accurately identifying Q1, Q3, and calculating the IQR correctly, but the provided options do not match this corrected calculation, suggesting a reevaluation of the method or options might be necessary. Given the options, none directly match the correct calculation, indicating a possible error in the explanation or a misunderstanding of the question's requirements.

For the Data Set Below, Find the Upper Outlier Boundary 160176193144163146152158154184129\begin{array} { l l l l l l l l l l l } \hline 160 & 176 & 193 & 144 & 163 & 146 & 152 & 158 & 154 & 184 & 129 \\\hline\end{array}160​176​193​144​163​146​152​158​154​184​129​​

For the Data Set Below, Find the Upper Outlier Boundary $\begin{array} { l l l l l l l l l l l } \hline 160 & 176 & 193 & 144 & 163 & 146 & 152 & 158 & 154 & 184 & 129 \\\hline\end{array}$