$f ( x ) = \sqrt { 3 x } ; g ( x ) = - 2 x + 7$
Find $( f \cdot g ) ( x )$
A) $( f \cdot g ) ( x ) = \sqrt { 3 x } + 14 x$
B) $( f \cdot g ) ( x ) = - 2 x \sqrt { 3 x } + 7 \sqrt { 3 x }$
C) $( f \cdot g ) ( x ) = - 6 x + 7 \sqrt { 3 x }$
D) $( f \cdot g ) ( x ) = - 6 x ^ { 2 } + 21$

Question

Quizplus · Accepted Answer

The product $(f \cdot g)(x)$ means multiplying the functions $f(x)$ and $g(x)$ together: $f(x) \cdot g(x) = \sqrt{3x} \cdot (-2x + 7) = -2x\sqrt{3x} + 7\sqrt{3x}$.

f(x)=3x;g(x)=−2x+7f ( x ) = \sqrt { 3 x } ; g ( x ) = - 2 x + 7f(x)=3x​;g(x)=−2x+7

$f ( x ) = \sqrt { 3 x } ; g ( x ) = - 2 x + 7$