Solve the equation.
-$$\log _ { 7 } \left( x ^ { 2 } - 6 x \right) = 1$$
A) $\{ 7 , - 1 \}$
B) $\{ 7 \}$
C) $\{ - 7,1 \}$
D) $\{ 1 \}$

Name: Solve the equation. -\[\log _ { 7 } \left( x ^ { 2 } - 6 x \right) = 1\] A) $\{ 7 , - 1 \}$ B) $\{ 7 \}$ C) $\{ - 7,1 \}$ D) $\{ 1 \}$
Brand: Quizplus
Rating: 4.8 (42 reviews)

Question

Quizplus · Accepted Answer

First, convert the logarithmic equation to its exponential form: $7^1 = x^2 - 6x$. This simplifies to $x^2 - 6x - 7 = 0$. Factoring or using the quadratic formula gives the solutions $x = 7$ and $x = -1$.

Solve the Equation log⁡7(x2−6x)=1\log _ { 7 } \left( x ^ { 2 } - 6 x \right) = 1log7​(x2−6x)=1

Solve the Equation $\log _ { 7 } \left( x ^ { 2 } - 6 x \right) = 1$