Solve.
-$$x = \sqrt { 3 x + 40 }$$
A) $\{ 5,8 \}$
B) $\{ - 20 \}$
C) $\{ 8 \}$
D) $\{ - 5,8 \}$

Question

Quizplus · Accepted Answer

Squaring both sides of the equation $x = \sqrt{3x + 40}$ gives $x^2 = 3x + 40$. Rearranging, we get $x^2 - 3x - 40 = 0$, which factors to $(x - 8)(x + 5) = 0$, giving solutions $x = 8$ and $x = -5$. However, substituting $x = -5$ back into the original equation results in a contradiction, as the square root of a real number cannot be negative. Thus, the only valid solution is $x = 8$.

Solve - x=3x+40x = \sqrt { 3 x + 40 }x=3x+40​

Solve
- $x = \sqrt { 3 x + 40 }$