Solve.
-$$\frac { 2 } { x ^ { 2 } } = \frac { 1 } { x + 4 }$$
A) $\{ 1 - 3,1 + 3 \}$
B) $\{ 1 - \mathrm { i } \sqrt { 7 } , 1 + \mathrm { i } \sqrt { 7 } \}$
C) $\{ - 1 - i \sqrt { 7 } , - 1 + i \sqrt { 7 } \}$
D) $\{ - 1 - 3 , - 1 + 3 \}$

Question

Quizplus · Accepted Answer

The correct answer is A because the equation can be solved to get x = 1 - 3 or x = 1 + 3.

Solve - 2x2=1x+4\frac { 2 } { x ^ { 2 } } = \frac { 1 } { x + 4 }x22​=x+41​

Solve
- $\frac { 2 } { x ^ { 2 } } = \frac { 1 } { x + 4 }$