Solve.
-$$\frac { 1 } { x } + \frac { 1 } { x - 3 } = \frac { x - 2 } { x - 3 }$$

Question

Quizplus · Accepted Answer

To solve the equation, first find a common denominator, which is $x(x - 3)$. This gives: $$\frac{x + (x - 3)}{x(x - 3)} = \frac{x - 2}{x - 3}$$ Simplifying the numerator on the left side gives: $$\frac{2x - 3}{x(x - 3)} = \frac{x - 2}{x - 3}$$ Multiplying both sides by $x(x - 3)$ to eliminate the denominators gives: $$2x - 3 = x - 2$$ Solving for $x$ gives: $$x = 1$$ Therefore, the solution is $\{1\}$.

Solve - 1x+1x−3=x−2x−3\frac { 1 } { x } + \frac { 1 } { x - 3 } = \frac { x - 2 } { x - 3 }x1​+x−31​=x−3x−2​

Solve
- $\frac { 1 } { x } + \frac { 1 } { x - 3 } = \frac { x - 2 } { x - 3 }$