Solve.
-The length and width of a rectangle must have a sum of 28 feet. Find the dimensions of the rectangle whose area is as large as possible.
A) Length $14 \mathrm { ft }$; width $42 \mathrm { ft }$
B) Length $13 \mathrm { ft }$; width $15 \mathrm { ft }$
C) Length $14 \mathrm { ft }$; width $14 \mathrm { ft }$
D) Length $\frac { 1 } { 14 } \mathrm { ft }$; width $\frac { 13 } { 14 } \mathrm { ft }$

Question

Quizplus · Accepted Answer

The maximum area of a rectangle, given a fixed perimeter, is achieved when the rectangle is a square. Since the sum of the length and width is 28 feet, dividing this equally gives dimensions of 14 ft by 14 ft.

Solve -The Length and Width of a Rectangle Must Have 14ft14 \mathrm { ft }14ft

Solve
-The Length and Width of a Rectangle Must Have $14 \mathrm { ft }$