Provide an appropriate response.
-If $g ( x ) = \sqrt { 2 x + 3 }$, find $g ( 0 )$ and $g ( 39 )$.
A) $\mathrm { g } ( 0 ) = 0 ; \mathrm { g } ( 39 ) = 81$
B) $\mathrm { g } ( 0 ) = 0 ; \mathrm { g } ( 39 ) = 9$
C) $g ( 0 ) = \sqrt { 3 } ; g ( 39 ) = 81$
D) $g ( 0 ) = \sqrt { 3 } ; g ( 39 ) = 9$

Question

Quizplus · Accepted Answer

To find $g(0)$, substitute $x = 0$ into the function: $g(0) = \sqrt{2(0) + 3} = \sqrt{3}$. To find $g(39)$, substitute $x = 39$: $g(39) = \sqrt{2(39) + 3} = \sqrt{78 + 3} = \sqrt{81} = 9$.

Provide an Appropriate Response g(x)=2x+3g ( x ) = \sqrt { 2 x + 3 }g(x)=2x+3​

Provide an Appropriate Response $g ( x ) = \sqrt { 2 x + 3 }$