Solve the equation.
-$$\frac { 1 } { x - 7 } = \frac { 14 } { x ^ { 2 } - 49 }$$

Question

Quizplus · Accepted Answer

The equation simplifies to an identity because $x^2 - 49$ is the same as $(x - 7)(x + 7)$, making the right side of the equation $\frac{14}{(x - 7)(x + 7)}$. After simplifying, both sides of the equation are equivalent, indicating all real numbers are solutions except for the values that make the denominator zero, which are $x = 7$ and $x = -7$. Thus, the correct choice is the set of all real numbers excluding 7 and -7, not explicitly listed among the options, implying an understanding that the correct answer is "all real numbers with certain exclusions," which fits the description of choice D.

Solve the Equation 1x−7=14x2−49\frac { 1 } { x - 7 } = \frac { 14 } { x ^ { 2 } - 49 }x−71​=x2−4914​

Solve the Equation $\frac { 1 } { x - 7 } = \frac { 14 } { x ^ { 2 } - 49 }$