Multiply.
-$( x - 6 ) \left( x ^ { 2 } - 3 \right)$
A) $x ^ { 3 } - 9 x + 18$
B) $x ^ { 3 } - 6 x ^ { 2 } - 3 x + 18$
C) $x ^ { 3 } - 9 x ^ { 2 } + 18$
D) $x ^ { 3 } + 6 x ^ { 2 } + 3 x + 18$

Question

Quizplus · Accepted Answer

To multiply $(x - 6)(x^2 - 3)$, distribute each term in the first polynomial across the second polynomial: $x \cdot x^2 + x \cdot (-3) + (-6) \cdot x^2 + (-6) \cdot (-3)$, which simplifies to $x^3 - 3x - 6x^2 + 18$, or reordering the terms gives $x^3 - 6x^2 - 3x + 18$.

Multiply - (x−6)(x2−3)( x - 6 ) \left( x ^ { 2 } - 3 \right)(x−6)(x2−3)

Multiply
- $( x - 6 ) \left( x ^ { 2 } - 3 \right)$