Use substitution to factor the polynomial completely.
-$4 x ^ { 4 } + 4 x ^ { 2 } - 15$
A) $\left( 2 x ^ { 2 } - 3 \right) \left( 2 x ^ { 2 } + 5 \right)$
B) $\left( 4 x ^ { 2 } - 3 \right) \left( x ^ { 2 } + 5 \right)$
C) $\left( 2 x ^ { 2 } - 15 \right) \left( 2 x ^ { 2 } + 1 \right)$
D) $\left( 2 x ^ { 2 } + 3 \right) \left( 2 x ^ { 2 } - 5 \right)$

Question

Quizplus · Accepted Answer

By substituting $y = x^2$, the polynomial becomes $4y^2 + 4y - 15$, which factors as $(2y - 3)(2y + 5)$. Substituting back $x^2$ for $y$, we get $(2x^2 - 3)(2x^2 + 5)$.

Use Substitution to Factor the Polynomial Completely 4x4+4x2−154 x ^ { 4 } + 4 x ^ { 2 } - 154x4+4x2−15

Use Substitution to Factor the Polynomial Completely $4 x ^ { 4 } + 4 x ^ { 2 } - 15$