Factor completely.
-$$4 x ^ { 2 } + 9$$
A) $( 2 x + 3 ) ^ { 2 }$
B) $( 2 x - 3 ) ^ { 2 }$
C) $( 2 x + 3 ) ( 2 x - 3 )$
D) prime polynomial

Name: Factor completely. -\[4 x ^ { 2 } + 9\] A) $( 2 x + 3 ) ^ { 2 }$ B) $( 2 x - 3 ) ^ { 2 }$ C) $( 2 x + 3 ) ( 2 x - 3 )$ D) prime polynomial
Brand: Quizplus
Rating: 4.8 (35 reviews)

Question

Quizplus · Accepted Answer

The expression $4x^2 + 9$ is a sum of squares, which cannot be factored over the real numbers. Therefore, it is considered a prime polynomial in the context of real numbers.

Factor Completely 4x2+94 x ^ { 2 } + 94x2+9 A) (2x+3)2( 2 x + 3 ) ^ { 2 }(2x+3)2

Factor Completely $4 x ^ { 2 } + 9$ A) $( 2 x + 3 ) ^ { 2 }$