Factor.
-$x ^ { 3 } + 8$
A) $( x + 2 ) \left( x ^ { 2 } + 4 \right)$
B) $( x + 2 ) \left( x ^ { 2 } - 2 x + 4 \right)$
C) $( x - 8 ) ( x + 1 ) ( x - 1 )$
D) $( x - 2 ) \left( x ^ { 2 } + 2 x + 4 \right)$

Question

Quizplus · Accepted Answer

The expression $x^3 + 8$ is a sum of cubes, which can be factored as $(a^3 + b^3) = (a + b)(a^2 - ab + b^2)$. Here, $a = x$ and $b = 2$, so the factored form is $(x + 2)(x^2 - 2x + 4)$.

Factor - x3+8x ^ { 3 } + 8x3+8 A) (x+2)(x2+4)( x + 2 ) \left( x ^ { 2 } + 4 \right)(x+2)(x2+4)

Factor
- $x ^ { 3 } + 8$ A) $( x + 2 ) \left( x ^ { 2 } + 4 \right)$