Factor the polynomial completely.
-$$2 x ^ { 2 } y - 18 y ^ { 3 }$$
A) $2 y ( x + 3 y ) ( x - 3 y )$
B) $2 y ^ { 3 } ( x + 3 ) ( x - 3 )$
C) $2 y ( x + 3 y ) ^ { 2 }$
D) $2 y ( x - 3 y ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The polynomial $2x^2y - 18y^3$ can be factored by first taking out the common factor of $2y$, giving $2y(x^2 - 9y^2)$. Then, recognizing $x^2 - 9y^2$ as a difference of squares, it can be further factored into $2y(x + 3y)(x - 3y)$.

Factor the Polynomial Completely 2x2y−18y32 x ^ { 2 } y - 18 y ^ { 3 }2x2y−18y3

Factor the Polynomial Completely $2 x ^ { 2 } y - 18 y ^ { 3 }$