Solve the system of equations.
-$$\left\{ \begin{array} { l }
y = 3 x + 2 \
y = 8 x + 1
\end{array} \right.$$
A) $\left( \frac { 1 } { 5 } , \frac { 13 } { 5 } \right)$
B) $\left( \frac { 13 } { 5 } , \frac { 1 } { 5 } \right)$
C) $\{ ( x , y ) \mid y = 3 x + 2 \}$
D) $\varnothing$

Question

Solve the system of equations.
-$$\left\{ \begin{array} { l } 
y = 3 x + 2 \
y = 8 x + 1
\end{array} \right.$$
A) $\left( \frac { 1 } { 5 } , \frac { 13 } { 5 } \right)$
B) $\left( \frac { 13 } { 5 } , \frac { 1 } { 5 } \right)$
C) $\{ ( x , y ) \mid y = 3 x + 2 \}$
D) $\varnothing$

Quizplus · Accepted Answer

To solve the system, set the two equations equal to each other: $3x + 2 = 8x + 1$. Solving for $x$, we get $x = \frac{1}{5}$. Substituting $x = \frac{1}{5}$ into one of the equations gives $y = \frac{13}{5}$. Therefore, the solution is $\left( \frac{1}{5}, \frac{13}{5} \right)$.

Solve the System of Equations {y=3x+2y=8x+1\left\{ \begin{array} { l } y = 3 x + 2 \\y = 8 x + 1\end{array} \right.{y=3x+2y=8x+1​

Solve the System of Equations $\left\{ \begin{array} { l } y = 3 x + 2 \\y = 8 x + 1\end{array} \right.$