Solve the equation.
-$\frac { 2 x - 1 } { 6 } + x = \frac { 2 x + 1 } { 2 } + 4$
A) $\{ 14 \}$
B) {6}
C) $\{ - 13 \}$
D) $\left\{ - \frac { 8 } { 3 } \right\}$

Question

Solve the equation.
-$\frac { 2 x - 1 } { 6 } + x = \frac { 2 x + 1 } { 2 } + 4$
A) $\{ 14 \}$
B)  {6} 
C) $\{ - 13 \}$
D) $\left\{ - \frac { 8 } { 3 } \right\}$

Quizplus · Accepted Answer

To solve the equation, first clear the fractions by multiplying every term by 6: $2x - 1 + 6x = 3(2x + 1) + 24$. Simplify to get $8x - 1 = 6x + 3 + 24$. Further simplify to $8x - 1 = 6x + 27$. Subtract $6x$ from both sides to get $2x - 1 = 27$. Add 1 to both sides to get $2x = 28$. Divide by 2 to find $x = 14$.

Solve the Equation 2x−16+x=2x+12+4\frac { 2 x - 1 } { 6 } + x = \frac { 2 x + 1 } { 2 } + 462x−1​+x=22x+1​+4

Solve the Equation $\frac { 2 x - 1 } { 6 } + x = \frac { 2 x + 1 } { 2 } + 4$