Solve.
-$\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$
A) $\left\{ 0 , \frac { 8 } { 3 } \right\}$
B) {0,8}
C) $\left\{ 0 , \frac { 1 } { 2 } \right\}$
D) $\phi$

Question

Solve.
-$\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$
A) $\left\{ 0 , \frac { 8 } { 3 } \right\}$
B)  {0,8} 
C) $\left\{ 0 , \frac { 1 } { 2 } \right\}$
D) $\phi$

Quizplus · Accepted Answer

The Answer of Solve.
-$\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$
A) $\left\{ 0 , \frac { 8 } { 3 } \right\}$
B)  {0,8} 
C) $\left\{ 0 , \frac { 1 } { 2 } \right\}$
D) $\phi$

Solve - ∣14x+1∣=∣12x−1∣\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|​41​x+1​=​21​x−1​

Solve
- $\left| \frac { 1 } { 4 } x + 1 \right| = \left| \frac { 1 } { 2 } x - 1 \right|$