The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+y^{2}-4 x-2 y-11=0$

A) center $( 2 , - 1 )$; radius $= 4$
B) center $( 2,1 )$; radius $= 4$
C) center $( - 2 , - 1 )$; radius $= 4$
D) center $( - 2,1 )$; radius $= 4$

Question

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+y^{2}-4 x-2 y-11=0$
 
A) center $( 2 , - 1 )$; radius $= 4$ 
B) center $( 2,1 )$; radius $= 4$ 
C) center $( - 2 , - 1 )$; radius $= 4$ 
D) center $( - 2,1 )$; radius $= 4$

Quizplus · Accepted Answer

The Answer of The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+y^{2}-4 x-2 y-11=0$
 
A) center $( 2 , - 1 )$; radius $= 4$ 
B) center $( 2,1 )$; radius $= 4$ 
C) center $( - 2 , - 1 )$; radius $= 4$ 
D) center $( - 2,1 )$; radius $= 4$

The Graph of the Equation Is a Circle x2+y2−4x−2y−11=0x^{2}+y^{2}-4 x-2 y-11=0x2+y2−4x−2y−11=0

The Graph of the Equation Is a Circle $x^{2}+y^{2}-4 x-2 y-11=0$