Find the value of the test statistic z using $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$ .
The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25 , and the sample statistics include n=696 drowning deaths of children with 30 % of them attributable to beaches.
A) 3.05
B) -3.05
C) -2.88
D) 2.88

Question

Find the value of the test statistic  z  using  $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$ .
The claim is that the proportion of drowning deaths of children attributable to beaches is more than  0.25 , and the sample statistics include  n=696  drowning deaths of children with  30 %  of them attributable to beaches.
A)  3.05 
B)  -3.05 
C)  -2.88 
D)  2.88

Quizplus · Accepted Answer

Given $p = 0.25$, $\hat{p} = 0.30$, $n = 696$, and $q = 1 - p = 0.75$, the test statistic $z$ is calculated as follows: $z = \frac{0.30 - 0.25}{\sqrt{\frac{0.25 \times 0.75}{696}}} = 3.05$.

Find the Value of the Test Statistic Z z=p^−ppqnz = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }z=npq​​p^​−p​

Find the Value of the Test Statistic Z $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$