$$\text { Find the value of the test statistic } z \text { using } z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } } \text {. }$$ pqn A claim is made that the proportion of children who play sports is less than 0.5, and the
Sample statistics include n = 1320 subjects with 30% saying that they play a sport.
A)14.53
B)29.66
C)−29.66
D)−14.53

Question

Quizplus · Accepted Answer

The test statistic z is calculated using the formula $ z = \frac{\hat{p} - p}{\sqrt{\frac{pq}{n}}} $, where $\hat{p} = 0.3$, $p = 0.5$, $q = 1 - p = 0.5$, and $n = 1320$. Substituting these values gives $ z = \frac{0.3 - 0.5}{\sqrt{\frac{0.5 \times 0.5}{1320}}} = -14.53 $.

Find the value of the test statistic z using z=p^−ppqn. \text { Find the value of the test statistic } z \text { using } z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } } \text {. } Find the value of the test statistic z using z=npq​​p^​−p​.

$\text { Find the value of the test statistic } z \text { using } z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } } \text {. }$