The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old (based on data from the Department of Transportation). The random variable x
Represents the number of cars that failed among six that were tested for roadworthiness: $$\begin{array} { | c | c | }
\hline \boldsymbol { x } & \boldsymbol { P } ( \boldsymbol { x } ) \
\hline 0 & 0.377 \
\hline 1 & 0.399 \
\hline 2 & 0.176 \
\hline 3 & 0.041 \
\hline 4 & 0.005 \
\hline 5 & 0 + \
\hline 6 & 0 + \
\hline
\end{array}$$ Find the probability of getting three or more cars that fail among six cars tested.
A)0.005
B)0.046
C)0.048
D)0.222

Question

The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old (based on data from the Department of Transportation). The random variable x
Represents the number of cars that failed among six that were tested for roadworthiness: $$\begin{array} { | c | c | } 
\hline \boldsymbol { x } & \boldsymbol { P } ( \boldsymbol { x } ) \
\hline 0 & 0.377 \
\hline 1 & 0.399 \
\hline 2 & 0.176 \
\hline 3 & 0.041 \
\hline 4 & 0.005 \
\hline 5 & 0 + \
\hline 6 & 0 + \
\hline
\end{array}$$ Find the probability of getting three or more cars that fail among six cars tested.
A)0.005
B)0.046
C)0.048
D)0.222

Quizplus · Accepted Answer

The probability of getting three or more cars that fail is found by adding the probabilities of getting exactly 3, 4, 5, or 6 cars that fail. This is $0.041 + 0.005 + 0 + 0 = 0.046$.

The Following Table Describes the Results of Roadworthiness Tests of Ford