Use the Principle of Mathematical Induction to prove that $$1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }$$ n ≥ 1.

Name: Use the Principle of Mathematical Induction to prove that \[1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }\] n ≥ 1.
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The Answer of Use the Principle of Mathematical Induction to prove that $$1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }$$ n ≥ 1.

Use the Principle of Mathematical Induction to Prove That 1+4+7+10+⋯+(3n−2)=n(3n−1)2 for all 1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }1+4+7+10+⋯+(3n−2)=2n(3n−1)​ for all

Use the Principle of Mathematical Induction to Prove That $1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }$