Find the sum.
-$\sum _ { j = 1 } ^ { 4 } j ( j + 8 )$
A) 110
B) 36
C) 48
D) 120

Question

Quizplus · Accepted Answer

The sum can be calculated by plugging in the values of $j$ from 1 to 4 into the given expression $j(j + 8)$ and then adding them together. For $j = 1$, the expression is $1(1 + 8) = 9$. For $j = 2$, it is $2(2 + 8) = 20$. For $j = 3$, it is $3(3 + 8) = 33$. For $j = 4$, it is $4(4 + 8) = 48$. Adding these together, $9 + 20 + 33 + 48 = 110$.

Find the Sum ∑j=14j(j+8)\sum _ { j = 1 } ^ { 4 } j ( j + 8 )∑j=14​j(j+8)

Find the Sum $\sum _ { j = 1 } ^ { 4 } j ( j + 8 )$