Find the sum.
-$$\sum _ { j = 1 } ^ { 6 } \frac { j + 4 } { j }$$
A) $\frac { 15 } { 2 }$
B) 45
C) $\frac { 54 } { 5 }$
D) $\frac { 79 } { 5 }$

Question

Quizplus · Accepted Answer

The sum can be calculated by evaluating each term individually and then adding them together: $$\sum _ { j = 1 } ^ { 6 } \frac { j + 4 } { j } = \frac { 1 + 4 } { 1 } + \frac { 2 + 4 } { 2 } + \frac { 3 + 4 } { 3 } + \frac { 4 + 4 } { 4 } + \frac { 5 + 4 } { 5 } + \frac { 6 + 4 } { 6 }$$ Simplifying each term gives: $$5 + 3 + \frac{7}{3} + 2 + \frac{9}{5} + \frac{5}{3}$$ Adding these together gives $\frac{79}{5}$.

Find the Sum ∑j=16j+4j\sum _ { j = 1 } ^ { 6 } \frac { j + 4 } { j }j=1∑6​jj+4​

Find the Sum $\sum _ { j = 1 } ^ { 6 } \frac { j + 4 } { j }$