Find the value of n so that the expression is a perfect square trinomial and then factor the trinomial.
-$$j ^ { 2 } - 4 j + n$$
A) $n = 2 ; ( j + 2 ) ^ { 2 }$
B) $n = 4 ; ( j - 2 ) ^ { 2 }$
C) $n = 4 ; ( j - 2 )$
D) $n = 2 ; ( j - 2 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

For a trinomial $a^2 - 2ab + b^2$ to be a perfect square, it must be in the form $(a - b)^2$. Here, $a = j$ and $2ab = 4j$, so $b = 2$. Thus, $n = b^2 = 4$, and the factored form is $(j - 2)^2$.

Find the Value of N So That the Expression Is j2−4j+nj ^ { 2 } - 4 j + nj2−4j+n

Find the Value of N So That the Expression Is $j ^ { 2 } - 4 j + n$