In Calculus you will see the symbol y'. Treat y' as a variable and solve the equation for y'.
-$$\frac { 6 x } { 23 } + \frac { 6 y } { 7 } y ^ { \prime } = 0$$
A) $y ^ { \prime } = \frac { 42 x } { 23 y }$
B) $y ^ { \prime } = - \frac { 42 x } { 23 y }$
C) $y ^ { \prime } = - \frac { 7 x } { 23 y }$
D) $y ^ { \prime } = \frac { 7 x } { 23 y }$

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The Answer of In Calculus you will see the symbol y'. Treat y' as a variable and solve the equation for y'.
-$$\frac { 6 x } { 23 } + \frac { 6 y } { 7 } y ^ { \prime } = 0$$
A) $y ^ { \prime } = \frac { 42 x } { 23 y }$
B) $y ^ { \prime } = - \frac { 42 x } { 23 y }$
C) $y ^ { \prime } = - \frac { 7 x } { 23 y }$
D) $y ^ { \prime } = \frac { 7 x } { 23 y }$

In Calculus You Will See the Symbol Y 6x23+6y7y′=0\frac { 6 x } { 23 } + \frac { 6 y } { 7 } y ^ { \prime } = 0236x​+76y​y′=0

In Calculus You Will See the Symbol Y $\frac { 6 x } { 23 } + \frac { 6 y } { 7 } y ^ { \prime } = 0$