Given that P(A or B)$= \frac { 1 } { 6 } , \mathrm { P } ( \mathrm { A } ) = \frac { 1 } { 8 } \text {, and } \mathrm { P } ( \mathrm { A } \text { and } \mathrm { B } ) = \frac { 1 } { 9 }$ find P(B) . Express the probability as a simplified fraction.
A) $\frac { 11 } { 72 }$
B) $\frac { 23 } { 432 }$
C) $\frac { 29 } { 72 }$
D) $\frac { 13 } { 72 }$

Question

Quizplus · Accepted Answer

The formula for the probability of A or B is $P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)$. Substituting the given values, we get $\frac{1}{6} = \frac{1}{8} + P(B) - \frac{1}{9}$. Solving for $P(B)$, we find $P(B) = \frac{1}{6} - \frac{1}{8} + \frac{1}{9} = \frac{11}{72}$.

Given That P(A or B) Find P(B) 1172\frac { 11 } { 72 }7211​

Given That P(A or B) Find P(B) $\frac { 11 } { 72 }$