What is the probability that in three consecutive rolls of two fair dice, a person gets a total of 7, followed by atotal of 11, followed by a total of 7? Round to the nearest ten-thousandth.
A) 0.0015
B) 0.1667
C) 0.2876
D) 0.0012

Question

Quizplus · Accepted Answer

The probability of getting a total of 7 on two fair dice is 6/36 = 1/6. The probability of getting a total of 11 on two fair dice is 2/36 = 1/18. So, the probability of getting a total of 7, followed by a total of 11, followed by a total of 7 is (1/6) * (1/18) * (1/6) = 1/324 = 0.0031. Rounded to the nearest ten-thousandth, this is 0.0031.

What Is the Probability That in Three Consecutive Rolls of Two