The table below describes the exercise habits of a group of people suffering from high blood pressure. If one ofthe 1046 subjects is randomly selected, find the probability that the person selected is female given that theyexercise occasionally. $\begin{array}{r|cccr}
& \begin{array}{c}
\text { No } \
\text { exercise }
\end{array} & \begin{array}{c}
\text { Occasional } \
\text { exercise }
\end{array} & \begin{array}{c}
\text { Regular } \
\text { exercise }
\end{array} & \text { Total } \
\hline \text { Men } & 384 & 85 & 74 & 543 \
\text { Women } & 345 & 69 & 89 & 503 \
\text { Total } & 729 & 154 & 163 & 1046
\end{array}$

A) 0.448
B) 0.066
C) 0.137
D) 0.147

Question

The table below describes the exercise habits of a group of people suffering from high blood pressure. If one ofthe 1046 subjects is randomly selected, find the probability that the person selected is female given that theyexercise occasionally. $\begin{array}{r|cccr} 
& \begin{array}{c}
\text { No } \
\text { exercise }
\end{array} & \begin{array}{c}
\text { Occasional } \
\text { exercise }
\end{array} & \begin{array}{c}
\text { Regular } \
\text { exercise }
\end{array} & \text { Total } \
\hline \text { Men } & 384 & 85 & 74 & 543 \
\text { Women } & 345 & 69 & 89 & 503 \
\text { Total } & 729 & 154 & 163 & 1046
\end{array}$

A) 0.448
B) 0.066
C) 0.137
D) 0.147

Quizplus · Accepted Answer

The probability that the person selected is female given that they exercise occasionally is calculated using the formula for conditional probability: P(A|B) = P(A and B) / P(B), where A is the event of being female and B is the event of exercising occasionally. Here, P(A and B) is the number of women who exercise occasionally (69), and P(B) is the total number of people who exercise occasionally (154). Thus, the probability is 69/154 = 0.448.

The Table Below Describes the Exercise Habits of a Group