Factor by grouping.
-$$3 x ^ { 2 } + 9 x y - 4 x y - 12 y ^ { 2 }$$
A) $( 3 x + 4 y ) ( x + 3 y )$
B) $\left( 3 x ^ { 2 } - 4 y \right) ( 1 + 3 y )$
C) $( 3 x - 4 y ) ( x - 3 y )$
D) $( 3 x - 4 y ) ( x + 3 y )$

Question

Quizplus · Accepted Answer

The expression can be grouped and factored as follows: $3x^2 + 9xy - 4xy - 12y^2 = 3x(x + 3y) - 4y(x + 3y) = (3x - 4y)(x + 3y)$.

Factor by Grouping 3x2+9xy−4xy−12y23 x ^ { 2 } + 9 x y - 4 x y - 12 y ^ { 2 }3x2+9xy−4xy−12y2

Factor by Grouping $3 x ^ { 2 } + 9 x y - 4 x y - 12 y ^ { 2 }$