Solve the equation.
-$$- 29 - ( 3 y - 1 ) = 2 ( y - 2 ) + 3 y$$
A) $\{ - 12 \}$
B) $\{ - 3 \}$
C) $\left\{ - \frac { 1 } { 3 } \right\}$
D) $\left\{ - \frac { 7 } { 2 } \right\}$

Question

Quizplus · Accepted Answer

Simplify both sides of the equation to get $-29 - 3y + 1 = 2y - 4 + 3y$. This simplifies to $-28 - 3y = 5y - 4$. Solving for $y$, we get $y = -3$.

Solve the Equation −29−(3y−1)=2(y−2)+3y- 29 - ( 3 y - 1 ) = 2 ( y - 2 ) + 3 y−29−(3y−1)=2(y−2)+3y

Solve the Equation $- 29 - ( 3 y - 1 ) = 2 ( y - 2 ) + 3 y$