Find the sum of the first 10 terms of the arithmetic sequence 88, 159, 230, . . . .
A) $- 3635$
B) 4075
C) $- 2315$
D) 3635

Question

Find the sum of the first 10 terms of the arithmetic sequence 88, 159, 230, . . . . 
A) $- 3635$
B) 4075
C) $- 2315$
D) 3635

Quizplus · Accepted Answer

The common difference (d) in the sequence is 159 - 88 = 71. The first term (a) is 88. The sum of the first n terms of an arithmetic sequence is given by $S_n = \frac{n}{2}[2a + (n-1)d]$. Substituting n = 10, a = 88, and d = 71, we get $S_{10} = \frac{10}{2}[2(88) + (10-1)71] = 5[176 + 9(71)] = 5[176 + 639] = 5[815] = 4075$.

Find the Sum of the First 10 Terms of the Arithmetic