Solve the inequality. -$x ^ { 2 } + 17 x

Name: Solve the inequality. -$x ^ { 2 } + 17 x 17$ B) $- 17 0$ D) $0 < x < 17$
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Question

Solve the inequality. -$x ^ { 2 } + 17 x < 0$ A) $x < 0 \text { or } x > 17$ B) $- 17 < x < 0$ C) $\mathrm { x } < - 17 \text { or } \mathrm { x } > 0$ D) $0 < x < 17$

Quizplus · Accepted Answer

To solve the inequality $x^2 + 17x < 0$, factor it to get $x(x + 17) < 0$. This inequality holds when one factor is negative and the other is positive. Since $x + 17$ becomes positive when $x > -17$, and $x$ is negative when $x < 0$, the solution is $-17 < x < 0$.

Solve the Inequality x2+17x<0x ^ { 2 } + 17 x < 0x2+17x<0

Solve the Inequality $x ^ { 2 } + 17 x < 0$