A compound gave a signal at 203 ppm in its ${}^{13 }\mathrm { C } \mathrm { NMR }$ spectrum. How would it be possible to tell if the compound is an aldehyde or a ketone in a proton-coupled ${}^{13} \mathrm { C } \text { NMR }$ pectrum?

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The Answer of A compound gave a signal at 203 ppm in its ${}^{13 }\mathrm { C } \mathrm { NMR }$ spectrum. How would it be possible to tell if the compound is an aldehyde or a ketone in a proton-coupled ${}^{13} \mathrm { C } \text { NMR }$ pectrum?

A Compound Gave a Signal at 203 Ppm in Its 13CNMR{}^{13 }\mathrm { C } \mathrm { NMR }13CNMR

A Compound Gave a Signal at 203 Ppm in Its ${}^{13 }\mathrm { C } \mathrm { NMR }$