Why is the $\mathrm { C } - \mathrm { H } \text { bond in ethene } \left( \mathrm { H } _ { 2 } \mathrm { C } = \mathrm { CH } _ { 2 } \right)$ shorter and stronger than the $\mathrm { C } - \mathrm { H }$ bond in ethane ($\left( \mathrm { CH } _ { 3 } \mathrm { CH } _ { 3 } \right)$

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The Answer of Why is the $\mathrm { C } - \mathrm { H } \text { bond in ethene } \left( \mathrm { H } _ { 2 } \mathrm { C } = \mathrm { CH } _ { 2 } \right)$ shorter and stronger than the $\mathrm { C } - \mathrm { H }$ bond in ethane ($\left( \mathrm { CH } _ { 3 } \mathrm { CH } _ { 3 } \right)$

Why Is The C−H bond in ethene (H2C=CH2)\mathrm { C } - \mathrm { H } \text { bond in ethene } \left( \mathrm { H } _ { 2 } \mathrm { C } = \mathrm { CH } _ { 2 } \right)C−H bond in ethene (H2​C=CH2​)

Why Is The $\mathrm { C } - \mathrm { H } \text { bond in ethene } \left( \mathrm { H } _ { 2 } \mathrm { C } = \mathrm { CH } _ { 2 } \right)$