Find the exact value of the real number y.
-$$y = \arcsin \left( - \frac { \sqrt { 3 } } { 2 } \right)$$

Question

Quizplus · Accepted Answer

The value of $\arcsin \left( - \frac { \sqrt { 3 } } { 2 } \right)$ corresponds to the angle in radians whose sine is $- \frac { \sqrt { 3 } } { 2 }$. This value is $- \frac { \pi } { 3 }$, as the sine of $\frac { \pi } { 3 }$ is $\frac { \sqrt { 3 } } { 2 }$, and the negative sign indicates the angle is in the fourth quadrant where sine values are negative.

Find the Exact Value of the Real Number Y y=arcsin⁡(−32)y = \arcsin \left( - \frac { \sqrt { 3 } } { 2 } \right)y=arcsin(−23​​)

Find the Exact Value of the Real Number Y $y = \arcsin \left( - \frac { \sqrt { 3 } } { 2 } \right)$