Solve the equation in the interval $$\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)$$ ). Give solutions to the nearest tenth, if necessary.
-$\sin ^ { 2 } \theta - \sin \theta - 12 = 0$

Question

Quizplus · Accepted Answer

The equation $\sin ^ { 2 } \theta - \sin \theta - 12 = 0$ can be solved by treating it as a quadratic equation in terms of $\sin \theta$. However, the roots of this equation will not correspond to any real angle $\theta$ because the equation implies values of $\sin \theta$ that are outside the possible range of $[-1, 1]$ for the sine function.

Solve the Equation in the Interval [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)[0∘,360∘)

Solve the Equation in the Interval $\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)$