Solve the equation for solutions in the interval [0 $$\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)$$ ). Round to the nearest degree.
-$$\cos ^ { 2 } \frac { \theta } { 2 } = 1$$

Question

Quizplus · Accepted Answer

The equation $\cos^2 \frac{\theta}{2} = 1$ implies that $\cos \frac{\theta}{2} = \pm 1$. This occurs when $\frac{\theta}{2} = 0^\circ, 360^\circ$, leading to $\theta = 0^\circ, 720^\circ$. However, within the interval $[0^\circ, 360^\circ)$, the only valid solution is $0^\circ$.

Solve the Equation for Solutions in the Interval [0 [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)[0∘,360∘)

Solve the Equation for Solutions in the Interval [0 $\left[ 0 ^ { \circ } , 360 ^ { \circ } \right)$