Find a general term an for the geometric sequence.
-$$a _ { 1 } = - \frac { 1 } { 7 } , r = - 6$$
A) $a _ { n } = - \frac { 1 } { 7 } \cdot ( - 6 ) ^ { n - 1 }$
B) $a _ { n } = \left( - \frac { 1 } { 7 } \right) ^ { n - 1 } + \frac { 1 } { 6 }$
C) $a _ { n } = - \frac { 1 } { 7 } - \frac { 1 } { 6 } ( n - 1 )$
D) $a _ { n } = - \frac { 1 } { 7 } + \frac { 1 } { 6 } ( n - 1 )$

Question

Quizplus · Accepted Answer

The general term of a geometric sequence is given by $a_n = a_1 \cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio. Here, $a_1 = -\frac{1}{7}$ and $r = -6$, so the correct formula is $a_n = -\frac{1}{7} \cdot (-6)^{n-1}$.

Find a General Term an for the Geometric Sequence a1=−17,r=−6a _ { 1 } = - \frac { 1 } { 7 } , r = - 6a1​=−71​,r=−6

Find a General Term an for the Geometric Sequence $a _ { 1 } = - \frac { 1 } { 7 } , r = - 6$