Use mathematical induction to prove that the statement is true for every positive integer n.
-$$6 + 2 \cdot 6 + 3 \cdot 6 + \ldots + 6 n = \frac { 6 n ( n + 1 ) } { 2 }$$

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The Answer of Use mathematical induction to prove that the statement is true for every positive integer n.
-$$6 + 2 \cdot 6 + 3 \cdot 6 + \ldots + 6 n = \frac { 6 n ( n + 1 ) } { 2 }$$

Use Mathematical Induction to Prove That the Statement Is True 6+2⋅6+3⋅6+…+6n=6n(n+1)26 + 2 \cdot 6 + 3 \cdot 6 + \ldots + 6 n = \frac { 6 n ( n + 1 ) } { 2 }6+2⋅6+3⋅6+…+6n=26n(n+1)​

Use Mathematical Induction to Prove That the Statement Is True $6 + 2 \cdot 6 + 3 \cdot 6 + \ldots + 6 n = \frac { 6 n ( n + 1 ) } { 2 }$